Question

Решите уравнение:а)x(x-3)=0;б)4x+x²=0;в)3x²-8x=0;г)y²+67y=0

Answer 1

a)
x (x - 3) = 0
x = 0 
x - 3 = 0 ==> x = 3 

b) 4x + x^2 = 0 
x (4 + x) = 0 
x = 0 ;
4 + x = 0 ==> x = - 4 

c) 3x^2 - 8x = 0 
x (3x  - 8) = 0 
x = 0 ;
3x - 8 = 0 ==> 3x = 8  ==> x = 8/3 = 2,(6)

d) y^2 + 6/7*y = 0 
y( y +  6/7) =  0
y = 0 
y+  6/7 = 0 ==> y = - 6/7 

Answer 2

1. x=0 x=3
2.x(4+x)=0 x=0 x=-4
3.x(3x-8) x=0  3x=8 x=8/3
4.y(y+6/7)=0 y=0 y=-6/7