Question

100a^4 - 1/9 b^2
9x^2 - ( x- 1)^2
x^3 + y^6

Answer 1

100a^4 - 1/9 b^2 =(10a²-1/3 b)(10a²+1/3 b)
9x^2 - ( x- 1)^2 =(3x-(x-1))(3x+(x-1))=(2x+1)(4x-1)
x^3 + y^6=(x+y²)(x²-xy²+y⁴)