Question

помогите высчитать массовую долю от H2CO3

Answer 1

Mr(H2CO3) = 1*2 + 12 + 16*3 = 62
W(H) = Ar(H) * n / Mr(H2CO3)  *100% = 1*2 / 62  *100% =3%
W(C) = Ar(C) * n / Mr(H2CO3)  *100% = 12*1 / 62  *100% = 19%
W(O) = Ar(O) * n / Mr(H2CO3)  *100% = 16*3 / 62  *100% =77%

Answer 2

Mr(H2CO3)=2*1+12+3*16=62
W(H)=2/62=0.03=3 %
W(C)=12/62=0.2=20%
W(O)=48/62=0.77=77%