Question

{(x+2)(x-3)>0 {x+1>0

Answer 1

$left { {(x+2)(x-3) textgreater 0} atop {x textgreater -1}} right. = left { { left { {{x textless -2} atop {x textgreater 3}} right. } atop {x textgreater -1}} right.$ ⇒ x∈(3;+∞)