Question

решите уравнения:x^3-3x^2-4x+12=0 и x^2+2x=16x-49

Answer 1

x^3 - 3x^2 - 4x + 12 = 0

x^2(x-3) - 4(x-3) = 0

(x^2-4)(x-3) = 0

(x-2)(x+2)(x-3) = 0

x = 2 или x = -2 или x = 3

Ответ: -2; 2; 3

2) x^2 + 2x - 16x + 49 = 0

x^2 -14x + 49 = 0

(x-7)^2 = 0

x = 7