Question

(x^2-8)^2+3 (x^2-8)=4

Answer 1

x^4-16x^2+64+3x^2-24=4
x^4-13x^2+36=0
x^4=t^2, x^2=t.
t^2-13t+36=0
D=(-13)^2-4•36=169-144=25 √25=5
t1=13-5/2=4. x1=16
t2=13+5/2=9. x2=81
Ответ: x1=16, x2=81.