Question

Если f (x)=2x^3-3x^2+6 то найдите значение f'(-2) и f'(2)

Answer 1

f ( x ) = 2x^3 - 3x^2 + 6 
f ' ( x ) = 6x^2 - 6x = 6x( x - 1 )
f ' ( - 2 ) = 6*( - 2 )*( - 2 - 1 ) = - 12*( - 3 ) = 36 
f ' ( 2 ) = 6*2*( 2 - 1 ) = 12