Question

8x = 12 /(x - 40) Решите

Answer 1

$8x= frac{12}{x-40}$
$8x= frac{12}{(x-40)} , x neq 0$
8x(x-40)-12=0
$8x^{2} -320x-12=0$
$4(2x^{2} -80x-3)=0$
$2x^{2} -80x-3=0$
$D=(-80)^{2} -4*2*(-3)= sqrt{6424}$
$x_{1} = frac{80-2 sqrt{1606} }{4} = frac{40- sqrt{1606} }{2}$
$x_{2} = frac{80+2 sqrt{1606} }{4} = frac{40+ sqrt{1606} }{2}$