Question

Lim стремится к 3 (x^2-2x-3)/(x^2-5x+6)

Answer 1

$lim_{x to 3} frac{x^2-2x-3}{x^2-5x+6} = lim_{x to 3} frac{(x-3)(x+1)}{(x-3)(x-2)} = \ = lim_{x to 3} frac{x+1}{x-2} = 4$