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1) По теореме Пифагора находим BH
![BH^{2} = AB^{2} - AH^{2} = 95^{2} - (19 sqrt{21})^{2} = 19^{2}*5^{2} - 19^{2}*21 = BH^{2} = AB^{2} - AH^{2} = 95^{2} - (19 sqrt{21})^{2} = 19^{2}*5^{2} - 19^{2}*21 =](https://tex.z-dn.net/?f=BH%5E%7B2%7D+%3D+AB%5E%7B2%7D+-+AH%5E%7B2%7D+%3D+95%5E%7B2%7D+-+%2819+sqrt%7B21%7D%29%5E%7B2%7D+%3D+19%5E%7B2%7D%2A5%5E%7B2%7D+-+19%5E%7B2%7D%2A21+%3D)
![= 19^{2}(25 - 21) = 19^{2}*2^{2} = 38^{2} = 19^{2}(25 - 21) = 19^{2}*2^{2} = 38^{2}](https://tex.z-dn.net/?f=%3D+19%5E%7B2%7D%2825+-+21%29+%3D+19%5E%7B2%7D%2A2%5E%7B2%7D+%3D+38%5E%7B2%7D+)
BH = 38
![cosB = frac{BH}{AB} = frac{38}{95} = frac{2}{5} cosB = frac{BH}{AB} = frac{38}{95} = frac{2}{5}](https://tex.z-dn.net/?f=cosB+%3D++frac%7BBH%7D%7BAB%7D+%3D++frac%7B38%7D%7B95%7D+%3D++frac%7B2%7D%7B5%7D+)
2) По теореме Пифагора находим BH
![BH^{2} = AB^{2} - AH^{2} = 45^{2} - 36^{2} = 9^{2}*5^{2} - 9^{2}*4^{2} = BH^{2} = AB^{2} - AH^{2} = 45^{2} - 36^{2} = 9^{2}*5^{2} - 9^{2}*4^{2} =](https://tex.z-dn.net/?f=BH%5E%7B2%7D+%3D+AB%5E%7B2%7D+-+AH%5E%7B2%7D+%3D+45%5E%7B2%7D+-+36%5E%7B2%7D+%3D+9%5E%7B2%7D%2A5%5E%7B2%7D+-+9%5E%7B2%7D%2A4%5E%7B2%7D+%3D)
![= 9^{2}(25 - 16) = 9^{2}*3^{2} = 27^{2} = 9^{2}(25 - 16) = 9^{2}*3^{2} = 27^{2}](https://tex.z-dn.net/?f=%3D+9%5E%7B2%7D%2825+-+16%29+%3D+9%5E%7B2%7D%2A3%5E%7B2%7D+%3D+27%5E%7B2%7D+)
BH = 27
BH = 38
2) По теореме Пифагора находим BH
BH = 27
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