Question

ПОМОГИТЕ,ОЧЕНЬ НАДО!!!!
(корень из 1+sinx )+cosx= 0

Answer 1

$sqrt{1+sin(x)} = - cos(x)$
Возведем в квадрат:
$(sqrt{1+sin(x)})^{2} = (-cos(x))^2 \ 1+ sin(x) - cos^2(x) = 0 \ sin^2(x) + sin(x) = 0 \ sin(x)*(sin(x)+1) = 0 \ sin(x) = 0; x = 0 + n pi \ sin(x) = -1; x = frac{3 pi}{2} + 2 pi n$