Question

решите пожалуйста 8 класс , алгебра , можнл с решением

Answer 1

4 3m–7 1–6m
-------- + ------------- = -------------------
3m+1 27m^3+1 1–3m+9m^2

4 3m–7
-------- + ----------------------------- –
3m+1 (3m+1)(9m^2–3m+1)

1–6m
– ------------------ = 0
1–3m+9m^2

36m^2–12m+4+3m–7–3m+18m^2–
----------------------------------------------------
(3m+1)(9m^2–3m+1)

–1+6m
---------- = 0

54m^2–6m–4
---------------------------- = 0
(3m+1)(9m^2–3m+1)

(3m+1)(9m^2–3m+1)=0 (не равно 0)
3m+1=0
3m=–1
m=–1/3
9m^2–3m+1=0
Д=/9–4*9*1 решений нет Д<0

54m^2–6m–4 = 0
Д=/36–4*54*(-4)=/900=30
m1=(6+30)/108=36/108=1/3
m2=(6–30)/108=–24/108 = –6/27
Ответ: m1=1/3; m2=–6/27