Question

реши уравнения
1)5t+30-12t=42
2)36×(x-3)=10-2×(x+2)

Answer 1

1) 5t+30-12t=42
-7t=42-30
-7t=12
t=-$frac{12}{7}$
t=-$1 frac{5}{7}$

2) 36*(х-3)=10-2*(х+2)
36х-108=10-2х-4
36х+2х=10-4+108
38х=114
х=114:38
х=3