Даны вектора AB(-1,3,-3) и BC (4,-5,1) найдите координаты и длину вектора AC.
2)Даны векторы a(3,1,-2) b(4,-1,-3) найдите координаты вектора 2а+b
Найти длину вектора а-3b если а (2,1,-5) b (-3,0,1
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![overline{AB}=(-1,3,-3)\overline{BC}=(4,-5,1)\\overline{AC}=overline{AB}+overline{BC}=(4-1,3-5,1-3)=(3,-2,-2)\|overline{AC}|=sqrt{3^2+2^2+2^2}=sqrt{17} overline{AB}=(-1,3,-3)\overline{BC}=(4,-5,1)\\overline{AC}=overline{AB}+overline{BC}=(4-1,3-5,1-3)=(3,-2,-2)\|overline{AC}|=sqrt{3^2+2^2+2^2}=sqrt{17}](https://tex.z-dn.net/?f=overline%7BAB%7D%3D%28-1%2C3%2C-3%29%5Coverline%7BBC%7D%3D%284%2C-5%2C1%29%5C%5Coverline%7BAC%7D%3Doverline%7BAB%7D%2Boverline%7BBC%7D%3D%284-1%2C3-5%2C1-3%29%3D%283%2C-2%2C-2%29%5C%7Coverline%7BAC%7D%7C%3Dsqrt%7B3%5E2%2B2%5E2%2B2%5E2%7D%3Dsqrt%7B17%7D)
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![overline{a}=(3,1,-2)\overline{b}=(4,-1,-3)\\2overline{a}+overline{b}=(6+4,2-1,-4-3)=(10,1,-7) overline{a}=(3,1,-2)\overline{b}=(4,-1,-3)\\2overline{a}+overline{b}=(6+4,2-1,-4-3)=(10,1,-7)](https://tex.z-dn.net/?f=overline%7Ba%7D%3D%283%2C1%2C-2%29%5Coverline%7Bb%7D%3D%284%2C-1%2C-3%29%5C%5C2overline%7Ba%7D%2Boverline%7Bb%7D%3D%286%2B4%2C2-1%2C-4-3%29%3D%2810%2C1%2C-7%29)
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![overline{a}=(2,1,-5)\overline{b}=(-3,0,1)\\overline{a}-3overline{b}=(2+9,1,-5-3)=(11,1,-8)\|overline{a}-3overline{b}|=sqrt{11^2+1^2+8^2}=sqrt{186} overline{a}=(2,1,-5)\overline{b}=(-3,0,1)\\overline{a}-3overline{b}=(2+9,1,-5-3)=(11,1,-8)\|overline{a}-3overline{b}|=sqrt{11^2+1^2+8^2}=sqrt{186}](https://tex.z-dn.net/?f=overline%7Ba%7D%3D%282%2C1%2C-5%29%5Coverline%7Bb%7D%3D%28-3%2C0%2C1%29%5C%5Coverline%7Ba%7D-3overline%7Bb%7D%3D%282%2B9%2C1%2C-5-3%29%3D%2811%2C1%2C-8%29%5C%7Coverline%7Ba%7D-3overline%7Bb%7D%7C%3Dsqrt%7B11%5E2%2B1%5E2%2B8%5E2%7D%3Dsqrt%7B186%7D)
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