Ответы
Ответ дал:
0
a)![frac{3x-(x-8)}{x-4}= frac{2x-8}{x-4}= frac{2(x-4)}{x-4} =2 frac{3x-(x-8)}{x-4}= frac{2x-8}{x-4}= frac{2(x-4)}{x-4} =2](https://tex.z-dn.net/?f=+frac%7B3x-%28x-8%29%7D%7Bx-4%7D%3D+frac%7B2x-8%7D%7Bx-4%7D%3D+frac%7B2%28x-4%29%7D%7Bx-4%7D+%3D2++)
б)![frac{y-x}{(y-3)(y+3)} - frac{x-3}{-(y^2-9)} = frac{y-x}{(y-3)(y+3)} + frac{x-3}{(y-3)(y+3)} \ frac{y-x+x-3}{(y-3)(y+3)}= frac{1}{y+3} frac{y-x}{(y-3)(y+3)} - frac{x-3}{-(y^2-9)} = frac{y-x}{(y-3)(y+3)} + frac{x-3}{(y-3)(y+3)} \ frac{y-x+x-3}{(y-3)(y+3)}= frac{1}{y+3}](https://tex.z-dn.net/?f=+frac%7By-x%7D%7B%28y-3%29%28y%2B3%29%7D+-+frac%7Bx-3%7D%7B-%28y%5E2-9%29%7D+%3D+frac%7By-x%7D%7B%28y-3%29%28y%2B3%29%7D+%2B+frac%7Bx-3%7D%7B%28y-3%29%28y%2B3%29%7D++%5C++frac%7By-x%2Bx-3%7D%7B%28y-3%29%28y%2B3%29%7D%3D+frac%7B1%7D%7By%2B3%7D++)
a)![frac{b-a}{ab} + frac{b-a}{b^2}= frac{b(b-a)+a(b-a)}{ab^2}= frac{b-ab+ab-a^2}{a^2}= frac{b^2-a^2}{ab^2} frac{b-a}{ab} + frac{b-a}{b^2}= frac{b(b-a)+a(b-a)}{ab^2}= frac{b-ab+ab-a^2}{a^2}= frac{b^2-a^2}{ab^2}](https://tex.z-dn.net/?f=+frac%7Bb-a%7D%7Bab%7D+%2B+frac%7Bb-a%7D%7Bb%5E2%7D%3D+frac%7Bb%28b-a%29%2Ba%28b-a%29%7D%7Bab%5E2%7D%3D+frac%7Bb-ab%2Bab-a%5E2%7D%7Ba%5E2%7D%3D+frac%7Bb%5E2-a%5E2%7D%7Bab%5E2%7D++++)
б)![x^2+ frac{2x^2}{x-2}= frac{x^2(x-2)+2x^2}{x-2}= frac{x^3-2x^2+2x^2}{x-2}= frac{x^3}{x-2} x^2+ frac{2x^2}{x-2}= frac{x^2(x-2)+2x^2}{x-2}= frac{x^3-2x^2+2x^2}{x-2}= frac{x^3}{x-2}](https://tex.z-dn.net/?f=x%5E2%2B+frac%7B2x%5E2%7D%7Bx-2%7D%3D+frac%7Bx%5E2%28x-2%29%2B2x%5E2%7D%7Bx-2%7D%3D+frac%7Bx%5E3-2x%5E2%2B2x%5E2%7D%7Bx-2%7D%3D+frac%7Bx%5E3%7D%7Bx-2%7D+++)
б)
a)
б)
Вас заинтересует
1 год назад
1 год назад
5 лет назад
5 лет назад
8 лет назад
8 лет назад
8 лет назад