Question

(4x+1)^2=(4x-2)^2 найдите корень уравнения

Answer 1

(4x+1)^2=(4x-2)^2

16x^2+8x+1=16x^2-16x+4

8x+1=-16x+4

8x+16x=4-1

24x=3

x=3/24


x=1/8=0.125