Question

log по основанию 4(x^-5x)=log по основанию 4 (x^+4)

Answer 1

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Answer 2

$x^2-5x=x^2+4;$$log_{4} (x^2-5x) = log_{4}(x^2+4);$

$x^2-5x=x^2+4; -5x=4; x=-0.8$

Ответ: - 0,8