Question

( 2x - 1 ) ( 16x + 2x + 1) = 23 + 4x (4x - 3) Ребят решите пж

Answer 1

(2x-1)(16x+2x+1)=23+4x(4x-3)

(2x-1)*(18x+1)=23+16x^2-12x

36x^2+2x-18x-1=23+16x^2-12x

36x^2-16x-1-23-16x^2+12x=0

20x^2-4x-24=0

4(5x^2-x-6)=0

4(5x^2+5x-6x-6)=0

4(5x-6)*(x+1)=0

(5x-6)*(x+1)=0

5x-6=0    x₁=6/5

x+1=0     x₂=-1