Question

(2 79z + 3 13)* 35= 16z+6 12

Answer 1

(2 79z + 3 13)* 35= 16z+6 12
(25/9z+10/3)*3/5=1/6z+13/2
5/3z+2=1/6z+13/2
11/6z=13/2-4/2
11z/6=9/2
22z=54
z=54/22=27/11=2 5/11
Ответ 2 5/11