Question

Решите тригонометрическое уравнение

Answer 1

$frac{2 - sinx + cos2x}{6x^2- pi x- pi ^2} = 0,$
$frac{2 - sinx + 1 - 2sin^2x}{(3x+ pi )(2x- pi )} = 0,$
$frac{- 2sin^2x - sinx + 3}{(3x+ pi )(2x- pi )} = 0,$
$frac{-(sinx-1)(2sinx+3)}{(3x+ pi )(2x- pi )} = 0,$
$left { {{sinx = 1,} atop {x neq - frac{ pi}{3} }, x neq frac{ pi}{2}.} right.$
$x = frac{5 pi }{2} + 2 pi n$