Question

Решите уравнение из вложения

Answer 1

(4x-5)√(2x^2-5x+3) = 0
4x -5 = 0
4x = 5
x1 = 5/4
√2x^2-5x+3 = 0
2x^2-5x+3 = 0
(2x-3)(x-1) = 0
2x - 3 = 0
2x = 3
x2 = 3/2
x - 1 = 0
x3 = 1
Ответ: 5/4, 3/2, 1