Question

4^(x)+12^(x)=2*36^(x)

Answer 1

4^x + 12^x = 2*36^x   /:36^x
4^x/36^x + 12^x/36^x = 2
(4/36)^x + (12/36)^x  - 2 =  0
(1/9)^x + (1/3)^x - 2 = 0 

Пусть (1/3)^x = t
t^2 + t -  2 = 0 
D = 1 + 8 = 9 
t1 = ( - 1 + 3)/2 = 1
t2 = ( - 1  - 3)/2 = - 2

Обратная замена
(1/3)^x = 1
x = 0 

(1/3)^x = - 2
Нет решений

Ответ
0