Question

Решите уравнение : ( x2-25)2 + (x2+3x - 102) = 0

Answer 1

$(x^2-25)^2+(x^2+3x-10)^2=0, \ ((x-5)(x+5))^2+((x-2)(x+5))^2=0, \ (x+5)^2((x-5)^2+(x-2)^2)=0, \ left [ {{(x+5)^2=0,} atop {(x-5)^2+(x-2)^2=0;}} right. left [ {{x+5=0,} atop { left { {{x-5=0,} atop {x-2=0;}} right. }} right. left [ {{x=-5,} atop { left { {{x=5,} atop {x=2;}} right. }} right. left [ {{x=-5,} atop {xinvarnothing; }} right. \ x=-5.$