Question

Решить уравнение $x^2-4|x|+3=0$

Answer 1

1) x^2 - 4x + 3 = 0
2) x^2 + 4x + 3 = 0

(1) x^2 - 4x + 3 = 0 
D = 16 - 12 = 4
x1 = ( 4 + 2)/2 = 6/2 = 3
x2 = (4 -  2)/2 = 2/2 = 1

(2) x^2 + 4x+  3 = 0
D = 16 - 12 = 4
x3 = ( - 4 + 2)/2 = - 2/2 =  - 1
x4 = ( - 4  - 2)/2 = - 6/2 = - 3