Question

Решить систему уравнений.........

Answer 1

x=3-y
(3-y)²-(3-y)y-y²=1
9-6y+y²-3y+y²-y²-1=0
y²-9y+8=0
D=(-9)²-4*8=81-32=49
y₁=(9-7)/2=1     x=3-1=2
y₂=(9+7)/2=8    x=3-8= -5

Ответ: (-5; 8) и (2; 1).

Answer 2

Vashe zadanie resheno