Question

дана функция y(x) = 2x^2+5x-3 найти y(0) y(1) y(-3) y (1/2)

Answer 1

y(0) = 2*0 + 5*0 - 3 = - 3
y(1) = 2*1 + 5*1 - 3 = 7 - 3 = 4
y(-3) = 2*9 - 5*3 - 3 = 3 - 3 = 0
y(1/2) = 2*0,25 + 5*0,5 - 3 = 0