Question

Задание на картинке

Answer 1

$(7,3sqrt[3]{49sqrt7}-0,3sqrt{7sqrt[3]{49}})^{frac{6}{11}}=\\=(7,3cdot sqrt[3]{7^2}cdor sqrt[6]7-0,3cdot sqrt7cdot sqrt[6]{7^2})^{frac{6}{11}}=(frac{73}{10}cdot 7^{frac{5}{6}}-frac{3}{10}cdot 7^{frac{5}{6}})^{frac{6}{11}}=\\=Big (7^{frac{5}{6}}cdot (frac{73}{10}-frac{3}{10})Big )^{frac{6}{11}}=7^{frac{5}{6}cdot frac{6}{11}}cdot 7^{frac{6}{11}}=7^{frac{5}{11}+frac{6}{11}}=7^1=7$