Question

2x²-2
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3x²+6x+3
сократите дробь

Answer 1

(2х^2 - 2)/(3х^2 + 6х + 3) = 2(х^2-1)/3(х^2 + 2х + 1) = 2(х-1)(х+1)/3(х+1)(х+1) = 2(х-1)/3(х+1) = (2х-2)/(3х+3).

Answer 2

2(x²-1)/3(x+1)²=2(x-1)(x+1)/3(x+1)(x+1)=2x-2/3x+3