Question

Вичислите 5*sin(-пи/2)+4*cos(0°)-cos(пи/6)^2

Answer 1

5sin(-п/2)+4сos0-cos^2(п/6)=5*(-1)+4*1-(√3/2)^2 = -5+4-3/4=-1-3/4=-1-0.75=-1.75