Question

решить уравнение: 6 /tg^2x + 5/ tgx -1=0

Answer 1

1/tgx = ctgx

$6ctg^{2}x + 5ctg^{x} - 1 = 0$

$(ctgx + 1)(6ctgx - 1) = 0$

$ctgx = -1 => x = -pi/4 + k_{1}pi$

$ctgx = 1/6 => x = arcctg(1/6) + k_{2}pi$