Question

y=e^3x-2cosx найти производные функции 

Answer 1

 

$y = e^{3x} - 2cosx\\ y' = (e^{3x} - 2cosx)' = boxed{ 3e^{3x} + 2sinx }$

 

Answer 2

y=e^3x-2cosx

y' = (e^3x) ' - (2cosx) ' = e^3x * (3x) ' + 2sinx =3e^3x + 2sinx