Question

Метод подстановки x-2y=1 2x-y=2

Answer 1

(x-2y=1;
(2x-y=2.;

(x =2y+1;
(2x-y=2;

(x = 2y +1;
(2 (2y+1) - y =2;

(x = 2y+1;
(4y+2-y=2;

(x =2y +1;
(3y+2 = 2;

(x = 2y +1;
(3y = 0;

(x =1;
(y=0.

(1;0)