Question

Решите данные неравенства
1)(х-1)(х+1)$leq$0
2)х(7-х) >0
3)х-2/3-х>0

Answer 1

$(x-1)(x+1) leq 0 \ x=1 \ x=-1$
x∈[-1;1]
$x(7-x) textgreater 0 \ x=0 \ x=7$
x∈(0;7)
$frac{x-2}{3-x} textgreater 0 \ x neq 3 \ frac{(x-2)(3-x)}{(3-x)} textgreater 0 \ x-2 textgreater 0 \ x textgreater 2$
x∈(2;3)∪(3;+oo)