Question

Решить: √6sinx+cos2x≤1

Answer 1

sqrt(6)sinx-sin^2x-cos^2x+cos^2x-sin^2x<=1

sqrt(6)sinx-2sin^2x<=0

sinx(sqrt(6)-2sinx)<=0

sqrt(6)>2sinx

sinx<=0

[П+2Пk;2П+2Пk]