Question

Помогите решить цепочку:
1)CaC$O_{3}$ -> Ca$C_{2}$=>$C_{2}H_{2} =\ \textgreater \ C_{6}H_{6}$

2) $C_{2}H_{2} =\ \textgreater \ H_{3} - CHO =\ \textgreater \ CH_{3}CH_{2}OH$

3) $C_{2}H_{2} =\ \textgreater \ C_{2}H_{4}$

Answer 1

1)
CaCO3 + 4C = CaC2 + 3CO
CaC2 + 2H2O = Ca(OH)2 + C2H2
3С2Н2  =  С6Н6 (t, C)
2)
C2H2 + H2O = CH3CHO 
CH3CHO + H2 = CH3CH2OH
3)
C2H2 + H2 = C2H4 (катализатор - Ni, Pt)