Question

разложить на множители 1) 36q2 - 25 2) 1 -81х2 3) 100a4 - 81b6 4) a6 - 4 5) p2 - a2 b2 9/4x2 - 1/100

Answer 1

$36q^2-25=(6q-5)(6q+5) \ 1-81x^2=(1-9x)(1+9x) \ 100a^4-81b^6=(10a^2-9b^3)(10a^2+9b^3) \ a^6-4=(a^3-2)(a^3+2) \ p^2-a^2b^2=(p-ab)(p+ab) \ frac{9}{4}x^2 - frac{1}{100}=(frac{3}{2}x - frac{1}{10})(frac{3}{2}x+frac{1}{10})$

Answer 2

$1)36q^2-25=(6q-5)(6q+5)$

$2)1-81x^2=(1-9x)(1+9x)$

$3)100a^4-81b^6=(10a^2-9b^3)(10a^2+9b^3)$

$4)a^6-4=(a^3-2)(a^3+2)$

$5)p^2-a^2b^2=(p-ab)(p+ab)$

$6)frac{9}{4}x^2-frac{1}{100}=(1,5x-0,1)(1,5x+0,1)$