Question

ДАЮ 50 БАЛЛОВ, если поможите решить все задания)))

Answer 1

$21. \sqrt[5]{32a^7} \sqrt[5]{a^3} = \sqrt[5]{32a^{10}}=2a^2$

$22. \sqrt[3]{32}:2^{ \frac{2}{3} }- \sqrt{121}= \sqrt[3]{2^5}:2^{ \frac{2}{3} }- 11 =2^{ \frac{5}{3} }:2^{ \frac{2}{3} }- 11=2^{ \frac{5}{3}-\frac{2}{3} }- 11= \\ =2-11=-9$

$23. ((2m)^{ \frac{2}{3} })^{ \frac{9}{2} }:(4m)^{ \frac{1}{2} }=(2m)^{ \frac{2}{3} *\frac{9}{2} }:(4m)^{ \frac{1}{2} }=(2m)^3:(2m^{ \frac{1}{2} })=2^2m^{ \frac{5}{2} }= \\ 4m^{2,5}$

$24. \frac{54^{ \frac{1}{3} }*16^{ \frac{1}{2} }}{250^{ \frac{1}{3} }} =4(\frac{54}{250})^{ \frac{1}{3} } =4(\frac{27}{125})^{ \frac{1}{3} }=4(\frac{27^{ \frac{1}{3} }}{125^{ \frac{1}{3} }})=4(\frac{3}{5})=\frac{12}{5}=2,4$

$25. log_{ \frac{1}{3} }54- \frac{1}{3}log_{ \frac{1}{3} }8+log_{ \frac{1}{3} }81=log_{ \frac{1}{3} }54- log_{ \frac{1}{3} }8^{\frac{1}{3}}+log_{ \frac{1}{3} }81= \\log_{ \frac{1}{3} }54- log_{ \frac{1}{3} }2+log_{ \frac{1}{3} }81 =log_{ \frac{1}{3} }( \frac{54*81}{2} )=log_{ \frac{1}{3} }( 27*81)= \\ =log_{ \frac{1}{3} }( 3^3*3^4)=log_{ \frac{1}{3} } 3^7=7log_{\frac{1}{3} } 3=-7$