Question

Помогите,плез:Найти суму членов геометричной прогрессии(bn)
b3=3/8,а b1=3/2

Answer 1

b1•q^2=3/8
3/2•q^2=3/8
q^2=(3•2)/(8•3)
q^2=1/4
q=1/2; q=–1/2

b1 3/2
S = ------ = ------- = –3
q–1 –1/2

3/2
S = ------- = –1
–3/2