Question

2 tg 0 + 8 cos 3П/2 -6 sin П/3$2tg 0+8cos3P:2-6sin P:3$

Answer 1

2tg0=0;

cos3π/2=0 =>8cos3π/2=0

sinπ/3=√3/2 =>6sin π/3=3√3 =√27

 

0+0-√27=-√27=-3√3

Answer 2

$2~tg~0+8cos dfrac{3pi}2-6sindfrac{pi}3=\\=2cdot 0+8cdot 0-6cdot dfrac{sqrt3}2=-3sqrt3$