Question

$(x-1)(x+1)=2( x-3)^{2}- x^{2}$

Answer 1

$(x-1)(x+1)=2( x-3)^{2}- x^{2}$
$x^2-1=2( x^2-6x+9)- x^{2}$
$x^2-1=2 x^2-12x+18- x^{2}$
$x^2-1=x^2-12x+18$
$x^2-12x+18- x^{2} +1=0$
$-12x+19=0$
$-12x=-19$
$12x=19$
$x=1 \frac{7}{12}$
Ответ: $x=1 \frac{7}{12}$