Question

tg^2(3x+п/2)=1/3 тригонометрия явно не моё...

Answer 1

tg²(3x+π/2)=1/3
(tg(π/2+3x))²=1/3
(-ctg3x)²=1/3
√(-ctg3x)²=√(1/3)
|-ctg3x|=1/√3
{-ctg3x=√3/3   ctg3x=-√3/3    3x=2π/3+πn     x₁=2π/9+πn/3
{ctg3x=√3/3    ctg3x=√3/3      3x=π/3+πn       x₂=π/9+πn/3.