Question

(х-1)в квадрате+(х+2)в квадрате-(х-3)(х+3)=22

Answer 1

(х-1)^2+(х+2)^2-(x-3)(x+3)=22
x^2-2x+1+x^2+4x+4-x^2+9=22
x^2+2x-8=0
D=4+32=36

x1;2= (-2+-6)/2
x1=2
x2=-4