Question

(2sin^2x-3cosx)/(2sinx-корень 3)=0

Answer 1

2sin^2x-3cosx=0
$2sin^2x-3cosx=0\2(1-cos^2x)-3cosx=0\-2cos^2x-3cosx+2=0\cos^2x+1.5cosx-1=0\cosx=1/2,x=-+frac{pi}{3}+2pi n;\cosx=-2\2sinx-sqrt3 =ni 0, \sinx= ni frac{sqrt3}{2}\x=ni frac{pi}{3}+2pi n;x=ni frac{2pi}{3}+2pi n\Otvet: x=-frac{pi}{3}+2pi n$