Question

Решите срочно 3 задание пж

Answer 1

$frac{c^2+4c+4}{c^2-4} : (c+2)=frac{(c+2)^2}{(c-2)(c+2)} cdot frac{1}{c+2} = frac{(c+2)^2}{(c-2)(c+2)^2} = frac{1}{c-2} \\c=-8; ; to ; ; frac{1}{c-2} = frac{1}{-8-2} =- frac{1}{10}=-0,1$