Question

номер 1168 (5,6), 1171(1,3)

Answer 1

$6ab^2-3b^2+2a^2b-ab=3b^2(2a-1)+ab(2a-1)= \ =(2a-1)(3b^2+ab)=b(2a-1)(3b+a) \ 2c^3-5c^2d-4c+10d=c^2(2c-5d)-2(2c-5d)=(2c-5d)(c^2-2)$

$6x^2+(2y-3x)(2y+3x)=6x^2+4y^2-9x^2=4y^2-3x^2 \ (5-2x)(5+2x)-(3-2x)(4-2x)=25-4x^2-(12-6x-8x+4x^2)= \ =25-4x^2-12+6x+8x-4x^2=13-8x^2+14x$