Question

Дано f(x)=x^2-3x Найти f(0)=? f(1); f(-3)

Answer 1

f(x)=x^2-3x

f(0)= 0^2-3*0 = 0

f(1) = 1^2-3*1=1-3= -2

f(-3) = (-3)^2 - 3*(-3) = 9 + 9 = 18