Question

x^3 - 3x^2 -4x +12 = 0
решите уравнение

Answer 1

x^3 - 3x^2 -4x +12 = 0
x^2(x-3)-4(x-3)=0
(x^2-4)(x-3)=0
(x-2)(x+2)(x-3)=0
x=2 x=3 x=-2