Question

4х+у=3 и 6х-2у=1,решите систему уравнений

Answer 1

$left { {{4x+y=3} atop {6x-2y=1}} right. left { {{8x+2y=6} atop {6x-2y=1}} right. 14x=7$

$x= frac{7}{14}= frac{1}{2}$

$4* frac{1}{2} +y=3 y=1$

$( frac{1}{2}; 1 )$