Question

Решите неравенство
f'(x)<= 0 .если f(x) =-2x^2+8x+7

Answer 1

f ( x ) = - 2x^2 + 8x + 7
f ' ( x ) = - 4х + 8
f ' ( x ) < = 0
- 4x + 8 < = 0
4x > = 8
x > = 2
[ 2 ; + бесконечность)