Question

Разложите на множители:
с^4-196

Answer 1

$c^4-196=c^4-sqrt{14}^4=(c^2)^2-(sqrt{14}^2)^2=(c^2-sqrt{14}^2)(c^2+sqrt{14}^2})=\=(c^2-14)(c^2+14)=(c-sqrt{14})(c+sqrt{14})(c^2+sqrt{14}).$